SOLUTION: Solve 64^x<32^(x+2. Thanks

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Question 42249: Solve 64^x<32^(x+2.
Thanks
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
From 64^x < 32^(x+2), we change eveything to powers of two...we get
(2^6)^x < (2^5)^(x+2)
2^(6x) < 2^(5x+10) and then
6x < 5x + 10
x < 10