SOLUTION: “There are seven less than twice the marbles in Tim’s box as there are in Amelia’s box. Chris has six more marbles than Amelia. How many marbles does Amelia have if together the th

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Question 422437: “There are seven less than twice the marbles in Tim’s box as there are in Amelia’s box. Chris has six more marbles than Amelia. How many marbles does Amelia have if together the three of them have 95 marbles?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
There are seven less than twice the marbles in Tim’s box as there are in Amelia’s box.
t = 2a-7
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Chris has six more marbles than Amelia.
c = a+6
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How many marbles does Amelia have if together the three of them have 95 marbles?
t + c + a = 95
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Substitute for "t" and for "c" and solve for "a":
(2a-7)+(a+6)+a = 95
4a -1 = 95
4a = 96
a = 24 (amelia's marbles)
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t = 2a-7 = 41 (tim's marbles)
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c = a + 6 = 30 (chris's marbles)
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Cheers,
Stan H.
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