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put this solution on YOUR website! Given that sinx(cosy + 2siny) - cosx(2cosy-siny) = 0, find the value of tan(x+y)
        sinx(cosy + 2siny) - cosx(2cosy - sin y) = 0
Remove the parentheses:
 sinx*cosy + 2sinx*siny - 2cosx*cosy + cosx*siny = 0
Rearrange the terms:
 sinx*cosy + cosx*siny - 2cosx*cosy + 2sinx*siny = 0
Factor -2 out of the 3rd and 4th terms:
sinx*cosy + cosx*siny - 2(cosx*cosy - sinx*siny) = 0
Use the identity sin(A + B)=sinA*cosB + cosA*sinB to rewrite the
first two terms:
           sin(x + y) - 2(cosx*cosy - sinx*siny) = 0
Use the identity cos(A + B)=cosA*cosB - sinA*sinB to rewrite the
two terms inside the parenthese:
                       sin(x + y) - 2*cos(x + y) = 0
Divide through by cos(x + y)
                       sin(x + y)   2*cos(x + y)       0 
                       覧覧覧覧覧 - 覧覧覧覧覧覧 = 覧覧覧覧覧
                       cos(x + y)    cos(x + y)    cos(x + y)
                  sin(A)  
Use the identity  覧覧覧 = tan(A)
                  cos(A) 
to rewrite the first term, and simplify the other terms:
                                  tan(x + y) - 2 = 0
                                      tan(x + y) = 2 
Edwin