Question 422281: I'm trying to solve when a man knows he has lost 12.4 percent of his weight, and now weighs 249.6. What was his starting weight?
I was thinking something like
12.4 249.6
_____ = _____
100 x
Can't recall how to do this.
Found 4 solutions by mananth, ikleyn, greenestamps, timofer:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website! let weight be x
now 249.6
...
if it was 100
it would increase to 112.4
100/112.4 = x/249.6
original weight = x=249.6*100/112.4
x= 222.06
Answer by ikleyn(53431)  (Show Source):
You can put this solution on YOUR website! .
I'm trying to solve when a man knows he has lost 12.4 percent of his weight,
and now weighs 249.6. What was his starting weight?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The solution in the post by @mananth is conceptually wrong and contradicts to common sense.
Indeed, according to his solution, the original weight (222.06 pounds) is less than it was after loosing (249.6 pounds).
It means that @mananth does not read his solutions, does not think about them and has no habit of self-checking.
Very dangerous person to be a tutor and especially to be an online tutor ( ! )
Let 'x' be the man's original weight, in pounds.
After loosing 12.4%, his weight is (x - 0.124x) = x*(1-0.124) = 0.876x pounds.
We equate it to the new weight, 249.6 pounds.
So, your equation is
0.876x = 249.6 pounds.
From this equation, we find
x =  = 284.93 (rounded).
ANSWER. The man's original weight was 284.93 pounds (approximately).
Solved correctly.
Answer by greenestamps(13258)  (Show Source):
Answer by timofer(136)  (Show Source):
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