SOLUTION: Laura hit a volleyball into the air with an initial upward velocity of 24 feet per second. The height h in feet of the ball above the ground can be moduled by
h=16t^2 24t+3, wher
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h=16t^2 24t+3, wher
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Question 422188: Laura hit a volleyball into the air with an initial upward velocity of 24 feet per second. The height h in feet of the ball above the ground can be moduled by
h=16t^2 24t+3, where t is the time in seconds above the ground.Find the time it takes the ball to reach 12 feet above the ground. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! h= -16t^2 + 24t+3, where t is the time in seconds above the ground.Find the time it takes the ball to reach 12 feet above the ground.
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The "h" is height; so let h = 12 and solve for "t":
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-16t^2+24t+3 = 12
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16t^2-24t+9 = 0
(4t-3)(4t-3) = 0
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t = 0.75 seconds
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Cheers,
Stan H.
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