SOLUTION: I need help on figuring this problem out please. The height of a triangle is three feet longer than the base. The area of the triangle is 44 square feet. Find the height and base o

Algebra ->  Triangles -> SOLUTION: I need help on figuring this problem out please. The height of a triangle is three feet longer than the base. The area of the triangle is 44 square feet. Find the height and base o      Log On


   

Question 422161: I need help on figuring this problem out please. The height of a triangle is three feet longer than the base. The area of the triangle is 44 square feet. Find the height and base of the triangle
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I need help on figuring this problem out please. The height of a triangle is three feet longer than the base. The area of the triangle is 44 square feet. Find the height and base of the triangle
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Area = (1/2)(base)*(height)
44 = (1/2)(x)(x+3)
22 = x^2+3x
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x^2+3x-22 = 0
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x = [-3 +- sqrt(9-4*-22)]/2
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x = [-3 +- sqrt(97)]/2
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Positive Solution:
x = [-3+sqrt(97)]/2 (base)
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x = [-3+sqrt(97) +6]/2
x = [3+sqrt(97)]/2 (height)
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Cheers,
Stan H.
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