SOLUTION: algebracially solve the system of equations. show your work. ax-by=b+a bx+ay=b+a
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Question 422028
:
algebracially solve the system of equations. show your work.
ax-by=b+a
bx+ay=b+a
Answer by
jim_thompson5910(35256)
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The key here is to eliminate one variable so we can solve for the other. So I'm going to eliminate y.
ax-by=b+a
bx+ay=b+a
a^2x-aby=ab+a^2
b^2x+aby=b^2+ab
Note: I multiplied both sides of the first equation by 'a' and both sides of the second equation by 'b'
Now add the two equations to get
a^2x+b^2x=a^2+2ab+b^2
(a^2+b^2)x=a^2+2ab+b^2
x=(a^2+2ab+b^2)/(a^2+b^2)
Now that we know that x=(a^2+2ab+b^2)/(a^2+b^2), we can use it to solve for 'y'. I'll let you do that.