SOLUTION: log 6 +log (x-3)=2 log y 2y-x=3

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Question 422024: log 6 +log (x-3)=2 log y
2y-x=3
Answer by edjones(8007) About Me  (Show Source):
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log 6 +log (x-3)=2 log y
10^(log 6)*10^(log (x-3))= 10^log y^2
6(x-3)=y^2
y^2=6x-18
2y-x=3
2y=x+3
y=(x+3)/2
(x^2+6x+9)/4=6x-18
x^2+6x+9=24x-72
x^2-18x+81=0
(x-9)^2=0
x=9
y=6
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Ed