SOLUTION: What is the vertex and line of symmetry of f(x)=1/5x^2? I can figure out the graph but the fraction throws me off for the other.

Algebra ->  Rational-functions -> SOLUTION: What is the vertex and line of symmetry of f(x)=1/5x^2? I can figure out the graph but the fraction throws me off for the other.      Log On


   

Question 422003: What is the vertex and line of symmetry of f(x)=1/5x^2? I can figure out the graph but the fraction throws me off for the other.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x)=1/5x^2   Vertex(0,0) Line of symmentry the y a-xis (or x = 0)



Note the Coefficient determines 2 things:

1) whether the parabola opens upward (>0 or downward(<0)

2) the broadness of the parabola

It has NO effect of the axis of symmetry. 

Note: blue graph is:  y = -5x^2