SOLUTION: A= theta. Prove and show all work (secA+tanA)/1 times the quantity (secA-tanA)=1

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Question 422002: A= theta. Prove and show all work
(secA+tanA)/1 times the quantity (secA-tanA)=1
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
(secA+tanA)/1 times the quantity (secA-tanA)=1

(secA+tanA)(secA-tanA)=1

sec^2(A)-tan^2(A)=1

1/cos^2(A)-sin^2(A)/cos^2(A)=1

[1-sin^2(A)]/cos^2(A)=1

cos^2(A)/cos^2(A)=1

1=1

So this verifies the identity.

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Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
(secA+tanA)/1 times the quantity (secA-tanA)=1
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Multiply to get:
sec^2 - tan^2 = 1
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1 = 1
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Cheers,
stan H.