SOLUTION: Find the foci and vertices of the ellipse with equation x^2/9+y^2/16=1

Algebra ->  Length-and-distance -> SOLUTION: Find the foci and vertices of the ellipse with equation x^2/9+y^2/16=1      Log On


   



Question 421929: Find the foci and vertices of the ellipse with equation x^2/9+y^2/16=1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center with a and b determining the respective vertices distances from center.
x^2/9+y^2/16=1
Center(0,0) Vertices: (3,0),(-3,0) and (0,4),(0,4)
foci distance from center along major axis: sqrt%2816-9%29+=+sqrt%287%29
foci: (0,sqrt(7)),(0,-sqrt(7))