SOLUTION: how do you solve log6x+ log6 (x+16)= 2 ?
Algebra
->
Exponential-and-logarithmic-functions
-> SOLUTION: how do you solve log6x+ log6 (x+16)= 2 ?
Log On
Algebra: Exponent and logarithm as functions of power
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Exponential-and-logarithmic-functions
Question 421859
:
how do you solve log6x+ log6 (x+16)= 2 ?
Answer by
solver91311(24713)
(
Show Source
):
You can
put this solution on YOUR website!
Presuming you are trying to represent base 6 logs, i.e.,
as opposed to base 10 logs,
:
First use "The sum of the logs is the log of the product":
Then use the definition of the logarithm function:
to write:
Standard form of the quadratic:
The quadratic factors. You can take it from here. You will need to exclude one of the roots because it is not in the domain of the logarithm function.
John
My calculator said it, I believe it, that settles it