SOLUTION: Solve each system of equations using the substitution method. 4x - y = 32y = -2 x + 70

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Question 421840: Solve each system of equations using the substitution method.
4x - y = 32y = -2 x + 70

Found 2 solutions by mananth, ikleyn:
Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
4x-y=32 .............1

y=70-2x
Plug the value of y in (1)
4x-1(70 -2x)=32
4x-70+2x=32
4x+2x=32 -70
6 x = 102
/ 6
x= 17
Plug the value of x in (1)
4 x + 1 y = 32
4 * 17 + 1 y = 32
68 + 1 y = 32
1 y = -36
/ 1
y= -36

Answer by ikleyn(53570) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve each system of equations using the substitution method.
4x - y = 32
y = -2x + 70
~~~~~~~~~~~~~~~~~~~~~~~~~~~~


        In the post by @mananth,  the solution and the answer are incorrect.
        I came to bring a correct solution. 


Your starting equations are

    4x - y = 32,     (1)
    y = -2x + 70.    (2)


Substitute expression (2) for y into equation (1)

    4x - (-2x + 70) = 32.


Simplify and find x

    4x + 2x - 70 = 32,

       6x = 32 + 70 = 102,

        x           = 102/6 = 17.


Now we are going to find y.
For it, substitute x = 17 into equation (2)        

    y = -2x + 70 = -2*17 + 70 = -34 + 70 = 36.


ANSWER.  The solution is x = 17, y = 36.

         Not y = -36, as mistakenly stated in solution by @mananth.

Solved correctly.