SOLUTION: I need help with this algebra question:
Three consecutive odd integers have a sum of 111.
Find the product of the smallest and largest of the three integers.
I was absent th
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-> SOLUTION: I need help with this algebra question:
Three consecutive odd integers have a sum of 111.
Find the product of the smallest and largest of the three integers.
I was absent th
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Question 421799: I need help with this algebra question:
Three consecutive odd integers have a sum of 111.
Find the product of the smallest and largest of the three integers.
I was absent the day they went through this in class. Thanks for the help c:
-Emily Found 2 solutions by Adrish, stanbon:Answer by Adrish(44) (Show Source):
You can put this solution on YOUR website! Solutions: Let the three consecutive odd integers are x,x+2 and x+4
Given sum of the three is 111
x+(x+2)+(x+4)=111
3x+6=111
3x=111-6
3x=105
x=105/3
x=35
Therefore the three consecutive odd integers are x=35
x+2=35+2=37
x+4=35+4=39
The product of the smallest and the largest integers are 35x 39=1365
You can put this solution on YOUR website! Three consecutive odd integers have a sum of 111.
Find the product of the smallest and largest of the three integers.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
Sum = 111
6x+3 = 111
6x = 108
x = 18
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1st: 2x-1 = 35
2nd: 37
3rd: 39
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Cheers,
Stan H.
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