SOLUTION: the perimeter of a rectangle is 104.The length exceeds the width by 32 inches. Find the length and the width.

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Question 421259: the perimeter of a rectangle is 104.The length exceeds the width by 32 inches. Find the length and the width.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The formula for perimeter is:
+P+=+2w+%2B+2l+
given:
l+=+w+%2B+32+
+P+=+104+
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By substitution:
+104+=+2w+%2B+2i+
+104+=+2w+%2B+2%2A%28+w+%2B+32%29+
+104+=+2w+%2B+2w+%2B+64+
4w+=+40+
+w+=+10+
and
l+=+w+%2B+32
l+=+10+%2B+32
l+=+42
The width is 10 and the length is 42
check answer:
+P+=+2w+%2B+2l+
+104+=+2%2A10+%2B+2%2A42+
104+=+20+%2B+84+
104+=+104
OK