SOLUTION: Please help me solve: Find the vertex, line of symmetry and the maximum, minimum value of f(x)=1/3(x+3)^2+6

Algebra ->  Rational-functions -> SOLUTION: Please help me solve: Find the vertex, line of symmetry and the maximum, minimum value of f(x)=1/3(x+3)^2+6      Log On


   

Question 421254: Please help me solve:
Find the vertex, line of symmetry and the maximum, minimum value of f(x)=1/3(x+3)^2+6
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
(x+3)(x+3)
x^2+3x+3x+9
x^2+6x+9
f(x)=1/3(x^2+6x+9)+6
vetex=(-3,6)
axis=-3
minimum=(-3,6)