SOLUTION: PLEASE HELP Find the area of the region limited by the curve y=(x+2)*(3x-3) and the axis x.
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-> SOLUTION: PLEASE HELP Find the area of the region limited by the curve y=(x+2)*(3x-3) and the axis x.
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Question 421204
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PLEASE HELP
Find the area of the region limited by the curve y=(x+2)*(3x-3) and the axis x.
Answer by
Gogonati(855)
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Solve:
(x^3+(3/2)x^2- 6x)|(-2, 1)=[1^3+3/2*1^2-6*1 ]-[(-2)^3+3/2*
(-2)^2-6(-2)]=25/2
Answer: The area under the curve is 25/2 square units.