SOLUTION: I do not understand the meaning of this problem and how to work it out, any help would be appreciated. Thanks, y varies jointly with x squared. If y = 1/4 when x=1, find the equa

Algebra ->  Functions -> SOLUTION: I do not understand the meaning of this problem and how to work it out, any help would be appreciated. Thanks, y varies jointly with x squared. If y = 1/4 when x=1, find the equa      Log On


   



Question 420104: I do not understand the meaning of this problem and how to work it out, any help would be appreciated. Thanks,
y varies jointly with x squared. If y = 1/4 when x=1, find the equation for y in terms of x

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y varies jointly with x squared.
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y = k*x^2
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Solve for "k" using " y = 1/4 when x=1"
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(1/4) = k*1^2
k = (1/4)
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Find the equation for y in terms of x
Equation:
y = (1/4)x^2
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cheers,
Stan H.
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