SOLUTION: a 17in piece of steel is cut into 3 pieces so that the second piece is twice as long as the first piece, and the third piece is 3in more than four times the length of the first pie
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Question 419977: a 17in piece of steel is cut into 3 pieces so that the second piece is twice as long as the first piece, and the third piece is 3in more than four times the length of the first piece Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! a 17in piece of steel is cut into 3 pieces so that the second piece is twice
as long as the first piece, and the third piece is 3in more than four times
the length of the first piece
:
Let x = length of the 1st piece
:
Write an equation for each phrase
:
"the second piece is twice as long as the first piece,"
2x = length of the 2nd piece
:
"the third piece is 3in more than four times the length of the first piece"
4x + 3 = length of the 3rd piece
:
Solve
x + 2x + (4x+3) = 17
7x = 17 - 3
7x = 14
x = 2 inches is the 1st piece.
I'll let you find the length of the other two pieces
