SOLUTION: Find two consecutive odd integers such that the square of the larger is 3 less than 12 times the smaller

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Question 41993: Find two consecutive odd integers such that the square of the larger is 3 less than 12 times the smaller
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X & (X+2) ARE THE TWO CONSECUTIVE ODD NUMBERS.
THEN (X+2)~2+3=12X OR X~2+4X+4+3=12X OR X~2-8X+7=0 OR (X-7)(X-1)=0 OR X=7 & X=1
THUS 7 & 9 ARE THE CONSECUTIVE ODD NUMBERS 9~2=81 & 12*7=84 THUS THE
SQUARE OF THE LARGER (81) IS 3 LESS THE 12*7=84