SOLUTION: Prove that the sum of the distances from any point in the interior of a equilateral triangle to each of the sides of the triangle is equal to the length of an altitude of that tria

Algebra ->  Geometry-proofs -> SOLUTION: Prove that the sum of the distances from any point in the interior of a equilateral triangle to each of the sides of the triangle is equal to the length of an altitude of that tria      Log On


   



Question 419848: Prove that the sum of the distances from any point in the interior of a equilateral triangle to each of the sides of the triangle is equal to the length of an altitude of that triangle.
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!

It's a little hard to draw here, but let x,y,z be the altitudes from D onto AB, BC, CA, respectively (segment x is perpendicular to AB, etc.). We know that the sum of the areas of the triangles ADB, BDC, CDA add up to the area of ABC, so

%28x%2AAB%29%2F2+%2B+%28y%2ABC%29%2F2+=+%28z%2ACA%29%2F2+=+%28h%2AAB%29%2F2 where h is the altitude from C onto AB.

Since the triangle is equilateral, AB+=+BC+=+CA and we can replace BC, CA with AB, without loss of generality.

%28x%2AAB%29%2F2+%2B+%28y%2AAB%29%2F2+%2B+%28z%2AAB%29%2F2+=+%28h%2AAB%29%2F2

We can multiply both sides by 2%2FAB, cancelling out the AB and 2. Hence, we obtain

x%2By%2Bz+=+h, as desired.