SOLUTION: Choose the answer that best represents the foci of an ellipse with the equation 25x^2+38y^2=900. (a) (-6, 0) (b) (+or- sqrt [11], 0) (c) (0, sqrt [11]) (d) (+or- sqrt [6], 0)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Choose the answer that best represents the foci of an ellipse with the equation 25x^2+38y^2=900. (a) (-6, 0) (b) (+or- sqrt [11], 0) (c) (0, sqrt [11]) (d) (+or- sqrt [6], 0)      Log On


   



Question 419818: Choose the answer that best represents the foci of an ellipse with the equation 25x^2+38y^2=900.
(a) (-6, 0)
(b) (+or- sqrt [11], 0)
(c) (0, sqrt [11])
(d) (+or- sqrt [6], 0)

Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
The equation of the ellipse is:
(25*x^2)/900)+(38*y^2)/900)=1
X^2/36+y^2/(450/19)=1
From the last equation we have: a=6 and b=sqrt(450/19)
c^2=36-(450/19)
c^2=36-23.6
c^2=12.3
c=3.5
The focee of the ellipse are:(-3.5,0) (3.5,0)