SOLUTION: sin-1(-(the square root of 3)/2) aka the angle whose sine is the (negative (square root of 3) divided by 2) the possible answers are A. -30 degrees B. -60 degrees C. 150 degree

Algebra ->  Trigonometry-basics -> SOLUTION: sin-1(-(the square root of 3)/2) aka the angle whose sine is the (negative (square root of 3) divided by 2) the possible answers are A. -30 degrees B. -60 degrees C. 150 degree      Log On


   



Question 41980: sin-1(-(the square root of 3)/2)
aka the angle whose sine is the (negative (square root of 3) divided by 2)
the possible answers are A. -30 degrees B. -60 degrees C. 150 degrees D. 120 degrees

Answer by abcdefg(37) About Me  (Show Source):
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sin-1(-(the square root of 3)/2)
aka the angle whose sine is the (negative (square root of 3) divided by 2)
the possible answers are A. -30 degrees B. -60 degrees C. 150 degrees D. 120 degrees
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sin-1=-sqrt3/2
(-sqrt3 is -1.732)
-1.732/2= -0.866
look up sin -0.866
sin -0.866 is -60 degrees
answer is -60 degrees
answer B