SOLUTION: I need to see the steps. Thanks 1. This intersection is four miles away from the locl firehouse. Due to rush hour traffic, the fire truck is only able to travel an average of 12

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Question 41971: I need to see the steps. Thanks
1. This intersection is four miles away from the locl firehouse. Due to rush hour traffic, the fire truck is only able to travel an average of 12mph. What is the minimum amount of time it will take the fire truck to reach the car fire?
2. The fire engine travels an average of 38mph. It takes the engine 15 minutes to get to the chemical plant. How far is the chemical plant?
Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
SOLUTION TO PART 1:
Distance to be traveled = 4 miles.
Speed of fire truck = 12 miles/hr.
Therefore, time taken by the fire truck to travel the distance = DISTANCE%2FSPEED = 4%2F12 = 1%2F3 hr. = 20 mins.

SOLUTION TO PART 2:
Speed of fire engine = 38 miles/hr.
Time of travel of the fire engine = 15 mins. = 1%2F4 hr.
Therefore, distance traveled by the fire engine in the given time = SPEEDxTIME = 38x1%2F4 = 19%2F2 = 9.5 miles.