Question 419685: Hi tutor, i do not get this question what so ever. It his a problem solving, algebraic question. I really need help. It would be greatly appreciated, thank you so much, may god bless you. Q : 500 tickets for a football game were sold and the total receipts were $105. Some of the tickets sold for $15 and the rest sold for 25cents. Find the number of each sold. ( i am required too provide a equation/formula , write a table i already have that set up : i have it as ticket 1 & ticket two & value, number and amount. & i also would greatly appreciate if you show the work as too how you got the answers, so i can learn from it. Thank you so much.
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! $15 tickets ----- x numbers
$0.25 tickets------y numbers
...
x+y = 500
15x+0.25y = 105
With dollar !5 ticket the system cannot be solved. you geta negative value
But if you take $0.15 as the value then it is possible to work out.
1 x + 1 y = 500 .............1
0.15 x + 0.25 y = 105 .............2
multiply (1)by 1
Multiply (2) by -4
1 x + 1 y = 500
-0.6 x + -1 y = -420
Add the two equations
0.4 x + 0 y = 80
/ 0.4
x= 200 $0.15 tickets
plug value of x in (1)
1 x + 1 y = 500
200 + 1 y = 500
1 y = 500 + -200
1 y = 300
y = 300 $0.25 ticket
|
|
|
