Question 419685: Hi tutor, i do not get this question what so ever. It his a problem solving, algebraic question. I really need help. It would be greatly appreciated, thank you so much, may god bless you. Q : 500 tickets for a football game were sold and the total receipts were $105. Some of the tickets sold for $15 and the rest sold for 25cents. Find the number of each sold. ( i am required too provide a equation/formula , write a table i already have that set up : i have it as ticket 1 & ticket two & value, number and amount. & i also would greatly appreciate if you show the work as too how you got the answers, so i can learn from it. Thank you so much.
Found 3 solutions by mananth, ikleyn, josgarithmetic:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website! $15 tickets ----- x numbers
$0.25 tickets------y numbers
...
x+y = 500
15x+0.25y = 105
With dollar !5 ticket the system cannot be solved. you geta negative value
But if you take $0.15 as the value then it is possible to work out.
1 x + 1 y = 500 .............1
0.15 x + 0.25 y = 105 .............2
multiply (1)by 1
Multiply (2) by -4
1 x + 1 y = 500
-0.6 x + -1 y = -420
Add the two equations
0.4 x + 0 y = 80
/ 0.4
x= 200 $0.15 tickets
plug value of x in (1)
1 x + 1 y = 500
200 + 1 y = 500
1 y = 500 + -200
1 y = 300
y = 300 $0.25 ticket
Answer by ikleyn(53538)  (Show Source):
You can put this solution on YOUR website! Hi tutor, i do not get this question what so ever. It his a problem solving, algebraic question. I really need help.
It would be greatly appreciated, thank you so much, may god bless you.
Q : 500 tickets for a football game were sold and the total receipts were $105.
Some of the tickets sold for $15 and the rest sold for 25cents.
Find the number of each sold.
( i am required too provide a equation/formula , write a table i already have that set up :
i have it as ticket 1 & ticket two & value, number and amount. & i also would greatly appreciate
if you show the work as too how you got the answers, so i can learn from it. Thank you so much.
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Regarding this problem, I'd like to make two notices.
First, the solution and the answer in the post by @mananth (300 tickets at $0.25 and 200 tickets by $15)
both are incorrect.
They do not withstand the check: 300*0.25 + 200*15 = 3075, not 105 dollars.
Second notice is that the problem is posed incorrectly. It is SELF-CONTRADICTORY and describes
a situation which NEVER may happen.
Indeed, 500 $0.25 tickets cost 500*0.25 = 5*25 = 125 dollars, which is just MORE than $105.
So, this problem, as it is presented in your post, is FATALLY DEFECTIVE and is only good
to throw it to a garbage bin.
Answer by josgarithmetic(39711)  (Show Source):
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