SOLUTION: A culture of bacteria obeys the law of uninhibited growth.
If 500 bacteria are present initially and there are 800 after 1 hour, how many will be present in the culture after 5
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If 500 bacteria are present initially and there are 800 after 1 hour, how many will be present in the culture after 5
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Question 419422: A culture of bacteria obeys the law of uninhibited growth.
If 500 bacteria are present initially and there are 800 after 1 hour, how many will be present in the culture after 5 hours? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A culture of bacteria obeys the law of uninhibited growth.
If 500 bacteria are present initially and there are 800 after 1 hour,
how many will be present in the culture after 5 hours?
:
Ao*2^kt = A
where
Ao = initial amt
k = constant value
t = time in hrs
A = resulting amt
:
500*2^1k = 800
2^k =
k*ln(2) = ln(1.6)
k =
k = .678
:
how many will be present in the culture after 5 hours?
A = 500*2^(.678*5)
A = 500*2^(.678*5)
A = 500*2^3.39
A = 500*10.4857
A = 5243 present in the culture after 5 hrs
