SOLUTION: The current of a river is 2 miles per hour. A boat travels to a point 8 miles upstream and back again in 3 hours. What is the speed of the boat in still water?

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Question 419040: The current of a river is 2 miles per hour. A boat travels to a point 8 miles upstream and back again in 3 hours.
What is the speed of the boat in still water?

Found 3 solutions by mananth, ikleyn, timofer:
Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
speed in still water = x
current speed 2

upstream speed = x-2
downstream speed = x+2

Distance= 16 miles

Time upstream + time downstream = 3hours
t=d/r
............
16/(x+2)+16/(x-2)=3
LCD = (x-2)(x +2)
16*(x-2)+16(x+2)=3
16x-32+ 16x+32=3(X^2-4)
32x=3X^2-12
3X^2-32 x-12=0
Use the quadratic formula
b^2-4ac= 1168
x=(32+sqrt(1168))/6
11.03 mph speed in still water




Answer by ikleyn(53427) About Me  (Show Source):
You can put this solution on YOUR website!
.
The current of a river is 2 miles per hour. A boat travels to a point 8 miles upstream and back again in 3 hours.
What is the speed of the boat in still water?
~~~~~~~~~~~~~~~~~~~~~~~~


        The solution and the answer in the post by @mananth both are incorrect.
        I came to bring a correct solution.


speed in still water =  x mph.			

current speed 		2 mph.		

					
upstream speed   = x-2 mph.		
downstream speed = x+2 mph.			
					
Distance = 	8 miles.			
					

Time equation

    8%2F%28x%2B2%29 + 8%2F%28x-2%29 = 3				.


    LCD = (x-2)*(x+2)								

    8*(x-2) + 8*(x+2) = 3				

    8x - 16+ 8x + 16 = 3(x^2-4)

    16x = 3x^2 - 12						

    3x^2 - 16x - 12=0	


Use the quadratic formula 

    b^2 - 4ac = (-16)^2 - 4*3*(-12) = 256 + 144 = 400

    x = %2816+%2B-+sqrt%28400%29%29%2F6				


Use positive root %2816+%2B+20%29%2F6 = 36%2F6 = 6.


ANSWER.  The speed of the boat in still water is 6 mph.

Solved correctly.



Answer by timofer(136) About Me  (Show Source):
You can put this solution on YOUR website!
Same distance 8 miles each way
s, speed of boat in still water
3 hours, total travel time

time = distance/speed
account for total travel time

8%2F%28s%2B2%29%2B8%2F%28s-2%29=3
Some steps, becomes a quadratic equation. Solve.

8%28s-2%29%2B8%28s%2B2%29=3%28s%2B2%29%28s-2%29
16s-16%2B16=3%28s%5E2-4%29
16s=3s%5E2-12
3s%5E2-16s-12=0
Try factoring. If not, use quadrati formula solution.

s=%2816%2B-+sqrt%2816%5E2%2B4%2A3%2A12%29%29%2F%282%2A3%29
s=%2816%2Bsqrt%28400%29%29%2F%282%2A3%29
s=%2816%2B20%29%2F6
s=36%2F6
s=6 which also check in the original equation.