SOLUTION: I need to see the steps to solving this quadratic equation x^2-2x-13=0 using the method from India and these equations also.
4x^2-4x+3=0
x^2+12x-64=0
2x^2-3x-5=0
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Quadratic Equations and Parabolas
-> SOLUTION: I need to see the steps to solving this quadratic equation x^2-2x-13=0 using the method from India and these equations also.
4x^2-4x+3=0
x^2+12x-64=0
2x^2-3x-5=0
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Question 418795: I need to see the steps to solving this quadratic equation x^2-2x-13=0 using the method from India and these equations also.
4x^2-4x+3=0
x^2+12x-64=0
2x^2-3x-5=0 Answer by ewatrrr(24785) (Show Source):
Hi
4x^2-4x+3=0
Move the constant term to the right side of the equation
4x^2-4x=-3
Multiply each term in the equation by four times the coefficient of the x^2 term
64x^2 -64x = -48
Square the coefficient of the original x term and add it to both sides of the equation
64x^2 -64x + 16 = -48 + 16
Take the square root of both sides and complete as shown
(8x -4)^2 =(-32)
(8x -4) = ± sqrt(-32)
x = (4 ± sqrt(-32))8
