SOLUTION: A passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi/h faster that the speed of the freight tra

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: A passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi/h faster that the speed of the freight tra      Log On


   

Question 41865This question is from textbook
: A passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi/h faster that the speed of the freight train, finfd the speed of each.
Thanks! This question is from textbook

Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the speed of friehgt train
Let x+25 be the speed of passenger train
Equation:
325(x)=200(x+25)
SOlve from there
Paul.