SOLUTION: find the measure of an angle such the difference between the measure of its supplement and 3 times the measure of the complement is 16 degrees
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Question 418577: find the measure of an angle such the difference between the measure of its supplement and 3 times the measure of the complement is 16 degrees Found 2 solutions by Gogonati, stanbon:Answer by Gogonati(855) (Show Source):
You can put this solution on YOUR website! Denote the unknown angle x degree, then its supplement is (180-x)degree and its complement is (90-x) degree. Since the difference between the supplement and three times the complement is 16 degree, we write the equation:
(180-x)-3(90-x)=16. The measure of unknown angle is 53 degree.
You can put this solution on YOUR website! find the measure of an angle such the difference between the measure of its supplement and 3 times the measure of the complement is 16 degrees
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angle: x
complement: 90-x
supplement: 180-x
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Equations:
180-x -(3(90-x)) = 16
180-x -270+3x = 16
2x - 90 = 16
2x = 106
x = 53 degrees
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Cheers,
Stan H.
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