SOLUTION: Solve the problem. Round your answers as needed
The resistance, in ohms, of a 25 foot piece of wire is given by the function R(d)= 025 / d^2 , where d is the diameter of the
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The resistance, in ohms, of a 25 foot piece of wire is given by the function R(d)= 025 / d^2 , where d is the diameter of the
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Question 41847: Solve the problem. Round your answers as needed
The resistance, in ohms, of a 25 foot piece of wire is given by the function R(d)= 025 / d^2 , where d is the diameter of the wire in inches. What happens to the resistance of the wire as the diameter of the wire decreases?
that is what the above should appear like Answer by tutorcecilia(2152) (Show Source):
You can put this solution on YOUR website! R(d) = 25/d^2 means that the resistance is a function of the diameter. To see how the size of the diameter effects resistance, plug in numbers for the diatmeter (d) and see what happens to the value of resistance (R):
Let d = 1:
R(1) = 25/1^1 = 25
.
Let d = 2
R(2) = 25/2^2 = 6.25
.
Let d = 5
R(5) = 25/5^2= 1
.
Let d = 10
R(10) = 25/10^2 = .25
So it seems that as the diameter (d) increases, the value of the resistance (R) decreases. This represents an inverse relationship between (d) and (R). Therefore, when (d) decreases, (R) increases. Try to plot these values to better visualize this inverse relationship between diameter and resistance.
