SOLUTION: A pay phone is holding a maximum number of 500 coins consisting of nickels, dimes and quarters. The number of quartes is twice the number of dimes.
If the value of all the coines
Algebra ->
Customizable Word Problem Solvers
-> Finance
-> SOLUTION: A pay phone is holding a maximum number of 500 coins consisting of nickels, dimes and quarters. The number of quartes is twice the number of dimes.
If the value of all the coines
Log On
Question 41837This question is from textbook
: A pay phone is holding a maximum number of 500 coins consisting of nickels, dimes and quarters. The number of quartes is twice the number of dimes.
If the value of all the coines is $88.00, how many nickles were in the pay phone? This question is from textbook
You can put this solution on YOUR website! Q+D+N=500 OR 2D+D+N=500 OR 3D+N=500 OR N=500-3D
25*2D+10D+5N=8800 SUB 500-3D FOR N & WE GET
50D+10D+5(500-3D)=8800 OR 60D+2500-15D=8800 OR 45D=6300 OR D=6300/45 OR D=140
140*10=1400 2D=280 OR 280*25=7000 & 500-140-280=80 OR 80*5=400
THUS 1400+7000+400=8800
THERE ARE 280 QUARTERS, 140 DIMES & 80 NICKLES.
(