You can put this solution on YOUR website! continuity corrections. estimate the probability of getting 55 girls in 100 births
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I guess you are asked to use a normal approximation to this
binomial probability.
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Find the z-scores for 54.5 and 55.5 when
u = np = 100(1/2) = 50
sigma = sqrt(npq) = sqrt(50(1/2)) = 5
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z(54.5) = (54.5-50)/5 = 0.9
z(55.5) = (55.5-50)/5 = 1.1
P(x = 55) = P(0.9 <= x <= 1.1) = 0.048394..
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The binomial answer is 0.048474
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Cheers,
Stan H.
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