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| Question 417965:  Mike has $1.75 in dimes and nickels. If he has 5 more nickels than dimes, how many of each coin does he have?
 ?  nickels
 ? dimes
 Answer by algebrahouse.com(1659)
      (Show Source): 
You can put this solution on YOUR website! "Mike has $1.75 in dimes and nickels. If he has 5 more nickels than dimes, how many of each coin does he have?" 
 x = number of dimes
 x + 5 = number of nickels {5 more nickels than dimes}
 
 10x + 5(x + 5) = 175 {value of each x number of each = total value of each}
 10x + 5x + 25 = 175 {used distributive property}
 15x + 25 = 175 {combined like terms}
 15x = 150 {subtracted 25 from both sides}
 x = 10 {divided both sides by 15}
 x + 5 = 15 {substituted 10, in for x, into x + 5}
 
 10 dimes and 15 nickels
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