SOLUTION: Let P1 be the proportion of successes in the first population and let P2 be the proportion of successes in the second population.
Testing:
H0: P1-P2=0
HA: P1-P2≠0
Sup
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Probability-and-statistics
-> SOLUTION: Let P1 be the proportion of successes in the first population and let P2 be the proportion of successes in the second population.
Testing:
H0: P1-P2=0
HA: P1-P2≠0
Sup
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Question 417897: Let P1 be the proportion of successes in the first population and let P2 be the proportion of successes in the second population.
Testing:
H0: P1-P2=0
HA: P1-P2≠0
Suppose z*=1.73
how do we find the p-value for the test to 4 decimal places? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Let P1 be the proportion of successes in the first population and let P2 be the proportion of successes in the second population.
Testing:
H0: P1-P2=0
HA: P1-P2≠0
Suppose z*=1.73
how do we find the p-value for the test to 4 decimal places?
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It's a 2-tail test so
the p-value = 2*P(z > 1.73) = 0.0836
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Cheers,
stan H.
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