SOLUTION: Can you please help me solve the following problem?
2^(4x+15)=5^(6-10x)
so far, I've done: log2(2^4x+15)=log2(5^6-10x)
4x+15=log2(5^6-10x)
but I do not know if this i
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Can you please help me solve the following problem?
2^(4x+15)=5^(6-10x)
so far, I've done: log2(2^4x+15)=log2(5^6-10x)
4x+15=log2(5^6-10x)
but I do not know if this i
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Question 417877: Can you please help me solve the following problem?
2^(4x+15)=5^(6-10x)
so far, I've done: log2(2^4x+15)=log2(5^6-10x)
4x+15=log2(5^6-10x)
but I do not know if this is the right way to procede with these problems. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Can you please help me solve the following problem?
2^(4x+15)=5^(6-10x)
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(4x+15)*log(2) = (6-10x)*log5
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[4log(2)+10log(5)]x = 6log(5)-15log(2)
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x = -0/3216/8.2938
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x = -0.03878..
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Cheers,
Stan H.
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