SOLUTION: divide and simplify 2x^2-7x-15/x^2-4 divided by 10x+15/x^2-4 i know you have to multiply by the reciprocal which cancels out the x^2-4. i am now stuck on the rest of the probl

Algebra ->  Rational-functions -> SOLUTION: divide and simplify 2x^2-7x-15/x^2-4 divided by 10x+15/x^2-4 i know you have to multiply by the reciprocal which cancels out the x^2-4. i am now stuck on the rest of the probl      Log On


   

Question 417491: divide and simplify
2x^2-7x-15/x^2-4 divided by 10x+15/x^2-4
i know you have to multiply by the reciprocal which cancels out the x^2-4.
i am now stuck on the rest of the problem..
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
divide and simplify
2x^2-7x-15/x^2-4 divided by 10x+15/x^2-4
i know you have to multiply by the reciprocal which cancels out the x^2-4.
----
Having canceled the (x^2-4) you have:
(2x^2-7x-15)/(10x+15)
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= (2x^2-10x+3x-15)/(5(2x+3))
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= (2x(x-5)+3(x-5))/(5(2x+3))
----
= ((x-5)(2x+3))/(5(2x+3))
----
= (x-5)/5
=================
Cheers,
Stan H.
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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

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|Yes, the (x^2-4) cancel by multiplying both numerator and denominator by (x^2-4)

%282x%5E2-7x-15%29%2F%2810x%2B15%29  

%28%282x%2B3%29%28x-5%29%29%2F5%282x%2B3%29=+%28x-5%29%2F5