SOLUTION: The length of a rectangule is 2 cm more than 5 times the width, the perimeter is 196 cm. find the width and length

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Question 417178: The length of a rectangule is 2 cm more than 5 times the width, the perimeter is 196 cm. find the width and length
Found 2 solutions by praseenakos@yahoo.com, jsmallt9:
Answer by praseenakos@yahoo.com(507) About Me  (Show Source):
You can put this solution on YOUR website!
let the width = x

length = x + 2
Perimeter = 196
2(length+ width ) = 196
+2%28x%2B2%2Bx%29+=+196
+2%282x%2B2%29+=+196
+2%282x%2B2%29%2F2+=+196%2F2
++2x%2B2++=+98
++2x%2B2-2+=+98-2
++2x+++=+96
++2x%2F2++=+96%2F2
++x++=++48
width = 48
so length = 48+2 = 50

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the width
Then the length which is "2 cm more than 5 times the width" would be: 2+5x
The perimeter is is the sum of 2 lengths and 2 widths. So
196 = 2*x + 2*(2+5x)
which simplifies to:
196 = 2x + 4 + 10x
196 = 12x + 4
Subtracting 4 from each side:
192 = 12x
Dividing both sides by 12:
16 = x
Since x was the width, the width is 16. The length is 2+5x. Since x = 16, the length would be 2 + 5(16) = 1 + 80 = 82.

So width = 16cm and length = 82cm.