SOLUTION: Please help me solve this equation: {{{(1 + x/12)^12 -1 = .259303}}}

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Question 416939: Please help me solve this equation: %281+%2B+x%2F12%29%5E12+-1+=+.259303
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me solve this equation:
%281+%2B+x%2F12%29%5E12+-1+=+.259303
add 1 to both sides:
%281+%2B+x%2F12%29%5E12+=+1.259303
:
log%28%281+%2B+x%2F12%29%5E12%29+=+log%28%281.259303%29%29
12%2Alog%28%281+%2B+x%2F12%29%29 = .100130238
log%28%281+%2B+x%2F12%29%29 = .100130238%2F12
log%28%281+%2B+x%2F12%29%29 = .00834418
find the anti-log of both sides (10^x)
1 + x%2F12 = 1.01934
x%2F12 = 1.01934 - 1
x%2F12 = .01934
Multiply both sides by 12
x = .23279
:
:
Check this in a calc: enter: (1 + (.23279/12))^12 - 1 results: .2593