Question 416851: log base 2 (x-2)+log base 2(8-x)-log base 2(x-5)=3
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! log base 2 (x-2)+log base 2(8-x)-log base 2(x-5)=3
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log2[(x-2)(8-x)/(x-5)] = 3
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[(x-2)(8-x)/(x-5)] = 8
(x-2)(8-x) = 8(x-5)
-x^2+10x-16 = 8x-40
x^2-18x-24 = 0
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Solve using the Quadratic Formula.
Discard values of "x" which cause
the original equation to have log2(negative number).
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Cheers,
Stan H.
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