SOLUTION: two ships leave port at the same time. Ship #1 travels north and ship #2 travels east. After 1 hour the ships are 25 miles apart. Ship #1 travels 5 miles faster than ship #2. How

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Question 416526: two ships leave port at the same time. Ship #1 travels north and ship #2 travels east. After 1 hour the ships are 25 miles apart. Ship #1 travels 5 miles faster than ship #2. How fast are the ships traveling.
I used the formula A^2 + b^2 = C^2 butr the answer is not right. Please help
X^2 + (X+5)^2 = 25 ^2
2x^2 + 10 X = 600
2x^2 = 60
X^2 = 30
x= 5.5

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+%28x%2B5%29%5E2++=+25%5E2
x%5E2+%2B+x%5E2+%2B+10x+%2B+25+=+625
2x%5E2+%2B+10x+=+600
x%5E2+%2B+5x+=+300
Complete the square
x%5E2+%2B+5x+%2B+%285%2F2%29%5E2+=+300+%2B+%285%2F2%29%5E2+
+%28x+%2B+%285%2F2%29%29%5E2+=+1200%2F4+%2B+25%2F4+
+%28x+%2B+%285%2F2%29%29%5E2+=+1225%2F4+
Take the square root of both sides
x+%2B+5%2F2+=+35%2F2
x+=+30%2F2
x+=+15
x+%2B+5+=+20
The ships are traveling 15 mi/hr and 20 mi/hr
check answer:
x%5E2+%2B+%28x%2B5%29%5E2++=+25%5E2
15%5E2+%2B+%2815%2B5%29%5E2++=+25%5E2
225+%2B+400+=+625
625+=+625
OK