SOLUTION: How much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get an 80%acid solution

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Question 416428: How much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get an 80%acid solution
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get an 80% acid solution
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Equation:
acid + acid = acid
0.40*2 + 1*x = 0.80(2+x)
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Multiply thru by 100 to get:
40*2 + 100x = 80*2 + 80x
20x = 40*2
x = 4 gallons (amt. of pure acid needed)
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Cheers,
Stan H.
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