SOLUTION: The directions for the problem is "Solve each equation for x to three significant digits” the problem is {{{ 5^x=3*4^x }}}. I tried changing it to {{{log (3*4^x) - log (5^x)=0 }}}
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-> SOLUTION: The directions for the problem is "Solve each equation for x to three significant digits” the problem is {{{ 5^x=3*4^x }}}. I tried changing it to {{{log (3*4^x) - log (5^x)=0 }}}
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Question 41642This question is from textbook Algebra with trigonometry
: The directions for the problem is "Solve each equation for x to three significant digits” the problem is . I tried changing it to but I couldn’t find anywhere to go after that. I would appreciate if you could help me figure this one out. Please and thanks! This question is from textbook Algebra with trigonometry
You can put this solution on YOUR website! Okay from
5^x = 3 * 4^x
take the log and get
log 5^x = log (3 * 4^x)
now apply power rule and multiplication rule and get
x*log 5 = log 3 + x*log 4
x*log 5 - x*log 4= log 3
x(log 5 - log 4)= log 3
x = log 3 / (log 5 - log 4)
then use your calculator