SOLUTION: The directions for the problem is "Solve each equation for x to three significant digits” the problem is {{{ 5^x=3*4^x }}}. I tried changing it to {{{log (3*4^x) - log (5^x)=0 }}}

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: The directions for the problem is "Solve each equation for x to three significant digits” the problem is {{{ 5^x=3*4^x }}}. I tried changing it to {{{log (3*4^x) - log (5^x)=0 }}}       Log On


   



Question 41642This question is from textbook Algebra with trigonometry
: The directions for the problem is "Solve each equation for x to three significant digits” the problem is +5%5Ex=3%2A4%5Ex+. I tried changing it to log+%283%2A4%5Ex%29+-+log+%285%5Ex%29=0+ but I couldn’t find anywhere to go after that. I would appreciate if you could help me figure this one out. Please and thanks! This question is from textbook Algebra with trigonometry

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Okay from
5^x = 3 * 4^x
take the log and get
log 5^x = log (3 * 4^x)
now apply power rule and multiplication rule and get
x*log 5 = log 3 + x*log 4
x*log 5 - x*log 4= log 3
x(log 5 - log 4)= log 3
x = log 3 / (log 5 - log 4)
then use your calculator