SOLUTION: Find three consecutive odd integers whose sum is 141

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Question 416392: Find three consecutive odd integers whose sum is 141
Found 2 solutions by htmentor, poliphob3.14:
Answer by htmentor(1343) About Me  (Show Source):
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Let the integers be n, n+2, n+4, since they are consecutive ODD integers
We have n+%2B+%28n%2B2%29+%2B+%28n%2B4%29+=+141
Solve for n: 3n+%2B+6+=+141 -> 3n+=+135+-%3E+n+=+45
Thus, the integers are: 45,47,49
Check: 45+47+49=141

Answer by poliphob3.14(115) About Me  (Show Source):
You can put this solution on YOUR website!
Solution: Three consecutive ood integers are: x, x+2, x+4. Since their sum is 141 we write the equation: x+x+2+x+4=141, 3x+6=141, 3x=135, x=45. The first ood number is 45, the second 45+2=47 and the third 47+2=49.
Proof: 45+47+49=141.