SOLUTION: One leg of a right triangle is 4 less than twice the other leg. If its hypotenuse is 10 how long are the two legs

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Question 416213: One leg of a right triangle is 4 less than twice the other leg. If its hypotenuse is 10 how long are the two legs
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
one leg = x
other leg = 2x-4
hypotenuse = 10
x^2+(2x-4)^2=100
x^2+4x^2-16x+16=100
5x^2-16x-84=0
5x^2-30x+14x-84=0
5x(x-6)+14(x-6)=0
(x-6)(5x+14)=0
x=6 one leg
other leg = 2x-4====> 12-4=8