SOLUTION: v=1/3 * π*r^(2)*h making h the subject We have this to solve making h the subject: {{{V/1=1/3*pi*r^2*h}}} cross multiply {{{1*pi*r^2*h=3*V}}} So we obtain {{{pi*r^2*h=3V

Algebra ->  College  -> Linear Algebra -> SOLUTION: v=1/3 * π*r^(2)*h making h the subject We have this to solve making h the subject: {{{V/1=1/3*pi*r^2*h}}} cross multiply {{{1*pi*r^2*h=3*V}}} So we obtain {{{pi*r^2*h=3V      Log On


   

Question 416178: v=1/3 * π*r^(2)*h making h the subject
We have this to solve making h the subject:
V%2F1=1%2F3%2Api%2Ar%5E2%2Ah
cross multiply
1%2Api%2Ar%5E2%2Ah=3%2AV
So we obtain
pi%2Ar%5E2%2Ah=3V
(we divide by pi%2Ar%5E2)
h=3V%2F%28pi%2Ar%5E2%29
Answer by dnanos(83) About Me  (Show Source):