SOLUTION: the set ( 1, 2, 3,......14) is partitioned into five subsets, each of which contains exactly 3 numbers. If the sum of the elements in each subset is to be the same, why can't (6, 8

Algebra ->  Average -> SOLUTION: the set ( 1, 2, 3,......14) is partitioned into five subsets, each of which contains exactly 3 numbers. If the sum of the elements in each subset is to be the same, why can't (6, 8      Log On


   



Question 416137: the set ( 1, 2, 3,......14) is partitioned into five subsets, each of which contains exactly 3 numbers. If the sum of the elements in each subset is to be the same, why can't (6, 8, 9) be one of these subsets?
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
It's already impossible, because there are fourteen elements, and we are partitioning the fourteen element set into five subsets of three elements each (note that by partitioning, the intersection of any two sets is empty).