Question 416084: A line passes through (-2,3), (2,5), and (6,k). Find k.
I've been finding the slope of the points, using that information to make a point slope {(y-y)=m(x-x)} equation, and turning that into a y=mx+b equation. However, I am not sure how I should go about solving this one.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A line passes through (-2,3), (2,5), and (6,k). Find k.
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slope = (5-3)/(2--2) = 2/4 = 1/2
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Equation Form:
y = mx = b
5 = (1/2)2 + b
b = 4
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Equation:
y = (1/2)x+4
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and (6,k). Find k
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y = (1/2)6+4 = 7
k = 7
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Cheers,
Stan H.
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