Question 415948: This is the only inverse-related section, so, here goes:
Find the inverse function of Y = (exp)3(sqrt)2x+1
I get that you turn f(x) into Y, and replace the X with Y, and vice versa; then move the (exp)3 onto the Y to get rid of the square root. So, it then becomes:
X^3 = 2Y+1
After that, I'm lost. If I subtract the 1, it becomes X^3-1 = 2Y, but, I can't divide by 2 because there needs to be an X in the denominator.
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! y = cbrt(2x+1)
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1st: Interchange to get:
x = cbrt(2y+1)
cube both sides:
x^3 = 2y+1
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2y+1 = x^3
2y = x^3 -1
y = (x^3-1)/2
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That is the inverse.
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Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source):
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